(x+1)(2x^2+3x+1)=

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Solution for (x+1)(2x^2+3x+1)= equation:


Simplifying
(x + 1)(2x2 + 3x + 1) = 0

Reorder the terms:
(1 + x)(2x2 + 3x + 1) = 0

Reorder the terms:
(1 + x)(1 + 3x + 2x2) = 0

Multiply (1 + x) * (1 + 3x + 2x2)
(1(1 + 3x + 2x2) + x(1 + 3x + 2x2)) = 0
((1 * 1 + 3x * 1 + 2x2 * 1) + x(1 + 3x + 2x2)) = 0
((1 + 3x + 2x2) + x(1 + 3x + 2x2)) = 0
(1 + 3x + 2x2 + (1 * x + 3x * x + 2x2 * x)) = 0
(1 + 3x + 2x2 + (1x + 3x2 + 2x3)) = 0

Reorder the terms:
(1 + 3x + 1x + 2x2 + 3x2 + 2x3) = 0

Combine like terms: 3x + 1x = 4x
(1 + 4x + 2x2 + 3x2 + 2x3) = 0

Combine like terms: 2x2 + 3x2 = 5x2
(1 + 4x + 5x2 + 2x3) = 0

Solving
1 + 4x + 5x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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